The distribution below has 60 observations and median 28.5. Classes 0–10, 10–20, 20–30, 30–40, 40–50, 50–60 have frequencies 5, x,20,15,y, 5. Find x and y.
Competition practiceStatistics
Ax=8,y=7
Bx=7,y=8
Cx=9,y=6
Dx=6,y=9
Step-by-Step Solution
45+x+y=60⇒x+y=15. Median class 20–30 (cf before it =5+x):28.5=20+2030−(5+x)×10⇒8.5=225−x⇒x=8, so y=7.
Answer: A) x=8,y=7
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