An inlet fills a school's sump in 8 hours, but a crack would empty the full sump in 40 hours. If the sump starts empty with both acting, after how many hours is it full?

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Accepted Answer

10. Net rate = 1/8 − 1/40 = 5/40 − 1/40 = 4/40 = 1/10 sump per hour, so it fills in 10 hours.

An inlet fills a school's sump in 8 hours, but a crack would empty the full sump in 40 hours. If the sump starts empty with both acting, after how many hours is it full?

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