- A40√3 m
- B20√3 m
- C60√3 m
- D40 m
Step-by-Step Solution
Distances: 60 cot 30° = 60√3 m and 60 cot 60° = 20√3 m. Walk 60√3 − 20√3 = 40√3 m ≈ 69.3 m.
Answer: A) 40√3 m
A 60 m tall building is seen from point A on the ground at an elevation of 30°. How far must one walk from A towards the building for the elevation to become 60°?
Competition practiceTrigonometry
Master this topic in 30 minutes a day.
Don't just memorise the answer — build a daily practice habit.
Practice 5 Similar Questions Free →All Trigonometry practice questions
More Trigonometry practice
From the top of a 96 m tower, the angles of depression of two cars on opposite sides of…A storm snaps a tree. The broken part bends over so that its top touches the ground 10 m…From the top of a 12 m building, the angle of elevation of the top of a tower is 30°;…From a point P at height h above a still lake, the angle of elevation of a cloud is α…Two observers A and B stand 1 km apart on a level road. A plane directly above the road…