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Find (sin 1° · sin 2° · sin 3° ⋯ sin 89°) ÷ (cos 1° · cos 2° · cos 3° ⋯ cos 89°).

Competition practiceTrigonometry
  • A1
  • B0
  • C89
  • D√2/2

Step-by-Step Solution

sin k° = cos(90 − k)°, so the numerator is exactly the denominator in reverse order. The ratio is 1.
Answer: A) 1

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