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From a point B on the ground, the top of a tower is seen at an elevation of 60°. Moving 50 m straight away from the tower to A, the elevation becomes 30°. How tall is the tower?

Competition practiceTrigonometry
  • A25√3 m
  • B50√3 m
  • C25 m
  • D50/√3 m

Step-by-Step Solution

h cot 30° − h cot 60° = 50, so h(√3 − 1/√3) = 50, i.e. 2h/√3 = 50 and h = 25√3 m.
Answer: A) 25√3 m

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