From the top of a 60 m high building, the angles of depression of the top and the bottom of a shorter building opposite it are 30° and 60°. Find the height of the shorter building.

Question

Accepted Answer

40 m. Gap = 60 60^° = 20\√3. Drop to its top = 20\√3 30^° = 20. Height = 60 - 20 = 40 m.

From the top of a 60 m high building, the angles of depression of the top and the bottom of a shorter building opposite it are 30° and 60°. Find the height of the shorter building.

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