Practice30Create account

In the series 9 N ! 3 P Q 6 E 1 V # 8 L 2 Z 7 A, how many pairs of letters are there with as many elements between them in the series as there are letters between them in the English alphabet?

Competition practiceAlphanumeric / Series
  • A3
  • B5
  • C2
  • D4

Step-by-Step Solution

The letters and their places are N (2), P (5), Q (6), E (8), V (10), L (13), Z (15), A (17). Four pairs match. N and V: seven elements lie between them in the series, and N is the 14th letter and V the 22nd, so seven letters lie between them in the alphabet. P and Q: none between in the series and none in the alphabet. P and Z: nine between in the series, and P (16th) to Z (26th) leaves nine in the alphabet. Q and Z: eight between in the series and eight in the alphabet. No other pair matches, so the answer is 4. Answering 3 comes of overlooking the neighbouring pair P and Q, whose count is nought on both sides; 5 comes of counting places rather than the elements between them; 2 of testing only pairs that stand close together.
Answer: D) 4

Master this topic in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Alphanumeric / Series practice questions

More Alphanumeric / Series practice

In the series 9 N ! 3 P Q 6 E 1 V # 8 L 2 Z 7 A, which element is fourth to the left of…In the series 9 N ! 3 P Q 6 E 1 V # 8 L 2 Z 7 A, what is the sum of the digits that…Every letter of the group HARP is replaced by the letter standing three places ahead of…In the letter series B, F, K, Q each letter is reached from the one before it by moving…Every letter of the group NQTW is replaced by the letter standing two places behind it…