Choose the odd one out: 91, 119, 145, 133.

91 = $7\times 13,119=7\times 17$ and $133=7\times 19$, so each is a multiple of 7. 145 breaks up as $5\times 29$ and carries no factor of 7. It is tempting because it lies in the same range and is odd like the rest, but the shared property is divisibility by 7.