- A7
- B6
- C8
- D4
Step-by-Step Solution
Count what each new cut can add. The first cut makes 2 pieces. The second cut can cross the first once, so it passes through 2 pieces and adds 2, making 4. The third cut can cross both earlier cuts, so it passes through 3 pieces and adds 3, making 7. The trap is 6: that is what you get from three cuts all through the centre, the arrangement everybody pictures first, but shifting the cuts off centre so that every pair crosses inside the pizza gains one extra piece. The trap 8 comes from assuming each cut simply doubles the count.
Answer: A) 7