Between the times on clocks A and B, how many times does the seconds hand pass over the minute hand? (Count only passes strictly after A.)

A shows 2:00:00 and B shows 2:10:00. The seconds hand gains $360-6=354^{\circ }$ per minute on the minute hand, so it passes it every $\frac{360}{354}=\frac{60}{59}$ min. In 10 min: $10÷\frac{60}{59}=9\frac{5}{6}$, so 9 passes. (10 assumes one pass a minute.)