Clocks A and B were both set right at 9:00 a.m. A gains 5 minutes every hour and B loses 3 minutes every hour. When A is exactly 1 hour ahead of B, what does clock B show?

Each true hour the gap between the clocks grows by 5 + 3 = 8 min, so a 60-min gap takes 60 ÷ 8 = 7.5 h: the true time is 4:30 p.m. B has lost $7.5\times 3=22.5$ min, so it shows 4:07:30 p.m. (4:30 p.m. is the true time; 5:07:30 p.m. is what A shows.)