- AP R M B
- B@ R M #
- C# R M @
- D& R M &
Step-by-Step Solution
First digit 4 and last digit 6 are both even, so condition (i) applies: first becomes # and last becomes @. The middle digits 7 and 2 code as R and M, giving # R M @.
Answer: C) # R M @
Digits are coded as 4=P, 7=R, 2=M, 9=K, 5=T, 6=B, 3=D. Conditions: (i) If both the first and the last digit are even, code the first digit as # and the last as @. (ii) If the first digit is odd and the last is even, code both as &. Code the number 4 7 2 6.
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