- A7
- B8
- C5
- D4
Step-by-Step Solution
From the net, 3 (above the centre) is opposite 1 (below it); in the row 4 5 2 6 the squares one apart are opposite, so 4–2 and 5–6. With 4 in front, 2 is at the back; with 6 on the right, 5 is on the left. The top and bottom must be the remaining pair, 3 and 1: . (7 assumes a standard die.)
Answer: D) 4