Three standard dice, whose opposite faces always total 7, are stacked as shown. What is the total number of dots on all the faces that cannot be seen, including the faces that touch each other and the table?

Question

Accepted Answer

43. Each die carries 1+2+ +6=21 dots, so the three dice have 63. The visible faces are the top 3 and the side pairs 3 and 1, 6 and 4, 1 and 2: 3+4+10+3=20. Hidden =63-20=43. (46 forgets to count the top face as visible.)

Three standard dice, whose opposite faces always total 7, are stacked as shown. What is the total number of dots on all the faces that cannot be seen, including the faces that touch each other and the table?

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