- A15 km
- B21 km
- C12 km
- D9 km
Step-by-Step Solution
Net east = 2 + 7 = 9 km; net north = 6 + 6 = 12 km. Distance = √ √225 = 15 km.
Answer: A) 15 km
Rahul walks 2 km east, 6 km north, 7 km east and then another 6 km north. What is the shortest distance between his final position and the starting point?
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