Ravi starts from his house and walks 4 km towards the North, then turns right and walks 3 km. What is the shortest distance between his starting point and his final position?

Question

Accepted Answer

5 km. The two legs (4 km North and 3 km East) are perpendicular. Shortest distance = √(4^2 + 3^2) = √(25) = 5 km.

Ravi starts from his house and walks 4 km towards the North, then turns right and walks 3 km. What is the shortest distance between his starting point and his final position?

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