- A(a)
- B(b)
- C(c)
- D(d)
Step-by-Step Solution
Every shaded part of A stays shaded in B, and the part just after it going clockwise is shaded as well, so each single part grows into a pair. In C the two neighbouring parts on the right become three, and the part on the upper left gains its clockwise neighbour at the top: (a). (b) adds the anticlockwise neighbours, (c) moves the parts round without keeping them and (d) shades the parts that were white.
Answer: A) (a)