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For the relation E > F ≥ G < H ≤ I, which conclusion is certainly true?

Competition practiceInequalities
  • AE > G
  • BF < I
  • CG ≥ I
  • DH > F

Step-by-Step Solution

E > F ≥ G gives E > G. F and I (or H and F) are joined through G with opposite signs, so they cannot be compared; G < H ≤ I makes G ≥ I false.
Answer: A) E > G

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