Four shelves are compared by height.
Statement: S ≥ T > U = V
Conclusions: I. S > V
II. T ≥ S
Which conclusion follows?

For I, compose S ≥ T, T > U and U = V. The first two give S > T only in the sense that S sits at or above T which is strictly above U, so S > U; the equality then carries this to S > V. Because the run contains the strict link T > U, the composite is strict, and I follows. For II, all that is stated about S and T is S ≥ T, which puts T at or below S. T ≥ S would additionally require them to be equal, and S = 9, T = 5, U = V = 1 satisfies every statement while making II false. So only I follows. 'Both' comes from reading S ≥ T as licensing the reverse relation too; 'Neither' from believing the opening non-strict link prevents any strict conclusion.