In a code: 'A @ B' = A is greater than B; 'A # B' = A is greater than or equal to B; 'A % B' = A is equal to B; 'A & B' = A is smaller than B; 'A * B' = A is smaller than or equal to B. Statements: P @ Q, Q # R, R % S. Conclusions: I. P @ S. II. R * P. Which conclusion(s) follow?

Question

Accepted Answer

Both conclusions follow. Decoding gives P > Q >= R = S, so P > S (I: P @ S). Also P > R and R = S give R < P, i.e. R <= P (II: R * P). Both hold.

In a code: 'A @ B' = A is greater than B; 'A # B' = A is greater than or equal to B; 'A % B' = A is equal to B; 'A & B' = A is smaller than B; 'A * B' = A is smaller than or equal to B. Statements: P @ Q, Q # R, R % S. Conclusions: I. P @ S.
II. R * P. Which conclusion(s) follow?

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More Inequalities practice

In a code: 'A @ B' = A is greater than B; 'A # B' = A is greater than or equal to B; 'A % B' = A is equal to B; 'A & B' = A is smaller than B; 'A * B' = A is smaller than or equal to B. Statements: P @ Q, Q # R, R % S. Conclusions: I. P @ S.II. R * P. Which conclusion(s) follow?

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Inequalities practice

In a code: 'A @ B' = A is greater than B; 'A # B' = A is greater than or equal to B; 'A % B' = A is equal to B; 'A & B' = A is smaller than B; 'A * B' = A is smaller than or equal to B. Statements: P @ Q, Q # R, R % S. Conclusions: I. P @ S.
II. R * P. Which conclusion(s) follow?