- AQ < R
- BP < S
- CP > S
- DR > P
Step-by-Step Solution
Decoding gives P > Q ≥ R = S, so P > S. The chain also makes Q ≥ R (not Q < R) and P > R (not R > P), so the other options fail.
Answer: C) P > S
In a code, 'A @ B' means A is greater than B; 'A # B' means A is less than B; 'A % B' means A is equal to B; 'A & B' means A is greater than or equal to B; 'A * B' means A is less than or equal to B. Given P @ Q, Q & R, R % S, which conclusion is definitely true?
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In a code, 'A @ B' means A is greater than B; 'A # B' means A is less than B; 'A % B'…In a code, 'A @ B' means A is greater than B; 'A # B' means A is less than B; 'A % B'…Given the statement A ≤ B < C, C = D, consider the conclusions: I. A < D. II. A = D.…In a code, 'A @ B' means A is greater than B; 'A # B' means A is less than B; 'A % B'…It is given that A > B > C > D and D > E. Which of the following is definitely true?