- AQ $ R
- BR & P
- CP % S
- DS % Q
Step-by-Step Solution
Decoding gives P ≥ Q > R = S, so P > S, which is 'P % S'. The rest contradict this chain (Q > R = S, and P need not equal or be below R).
Answer: C) P % S
In a code, '@' means ≥ (not smaller than), '#' means ≤ (not greater than), '$' means < (smaller than), '%' means > (greater than), and '&' means = (equal to). Given statements: P @ Q, Q % R, R & S. Which conclusion is definitely true?
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