In a code, 'P @ Q' means P ≥ Q, 'P # Q' means P ≤ Q, 'P $ Q' means P Q, 'P * Q' means P S). II. Q @ S (Q ≥ S). Which follows?

Question

In a code, 'P @ Q' means P ≥ Q, 'P # Q' means P ≤ Q, 'P $ Q' means P > Q, 'P * Q' means P < Q, and 'P ^ Q' means P = Q. Statements: P $ Q, Q @ R, R ^ S. Conclusions: I. P $ S (P > S). II. Q @ S (Q ≥ S). Which follows?

Accepted Answer

Both I and II follow. Decoding: P > Q, Q ≥ R, R = S. From P > Q ≥ R = S we get P > S (I). From Q ≥ R = S we get Q ≥ S (II). Both follow.

In a code, 'P @ Q' means P ≥ Q, 'P # Q' means P ≤ Q, 'P $ Q' means P > Q, 'P * Q' means P < Q, and 'P ^ Q' means P = Q. Statements: P $ Q, Q @ R, R ^ S. Conclusions: I. P $ S (P > S).
II. Q @ S (Q ≥ S). Which follows?

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More Inequalities practice

In a code, 'P @ Q' means P ≥ Q, 'P # Q' means P ≤ Q, 'P $ Q' means P > Q, 'P * Q' means P < Q, and 'P ^ Q' means P = Q. Statements: P $ Q, Q @ R, R ^ S. Conclusions: I. P $ S (P > S).II. Q @ S (Q ≥ S). Which follows?

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Inequalities practice

In a code, 'P @ Q' means P ≥ Q, 'P # Q' means P ≤ Q, 'P $ Q' means P > Q, 'P * Q' means P < Q, and 'P ^ Q' means P = Q. Statements: P $ Q, Q @ R, R ^ S. Conclusions: I. P $ S (P > S).
II. Q @ S (Q ≥ S). Which follows?