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Statements: P ≤ Q, Q < R, R ≤ S. Conclusions: I. P < R.
II. S > P.

Competition practiceInequalities
  • AOnly II is true
  • BNeither is true
  • CBoth I and II are true
  • DOnly I is true

Step-by-Step Solution

P ≤ Q < R gives P < R (I true). Then P < R ≤ S gives P < S, i.e. S > P (II true).
Answer: C) Both I and II are true

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