- AR § T
- BS § U
- CR § U
- DS ¤ T
Step-by-Step Solution
Decoded, the statements are R > S, S = T and T ≥ U, so the chain is R > S = T ≥ U. 'R § T' (R > T) follows, since S = T turns R > S into R > T. 'R § U' (R > U) follows, since R > T and T ≥ U compose to a strict result. 'S ¤ T' (S = T) is given outright. But 'S § U' claims S > U, and the only link between them is T ≥ U with S = T, which yields S ≥ U and no more: R = 9, S = T = 5, U = 5 satisfies every statement while making S > U false. That is the trap — the non-strict link T ≥ U allows equality, so it can support S ≥ U but never S > U.
Answer: B) S § U