Choose the expression that gives exactly the orange regions.

Orange: the A-only part and the $B-C$ lens outside A. $A\cup (B\cap C)$ gives A plus that lens; removing $A\cap (B\cup C)$ wipes out every part of A that touches $B$ or $C$, leaving exactly the two orange parts. $A\cup (B\cap C)$ alone keeps all of A, $(A-B)\cup (B\cap C)$ keeps the A–$C$ lens and the centre, and the symmetric difference keeps the A–$B$ and A–$C$ lenses.