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A tree is snapped by the wind but the broken part stays attached and leans over so that its tip touches the ground 8 m from the foot of the tree, making an angle of 30° with the ground. The original height of the tree was:

Competition practiceTrigonometry
  • A8√3 m
  • B8(√3 + 1) m
  • C16√3/3 m
  • D24 m

Step-by-Step Solution

The standing stump is 8·tan30° = 8/√3 m and the broken part (the slanting piece) is 8/cos30° = 16/√3 m. The original height is the sum, 24/√3 = 8√3 ≈ 13.86 m. Reporting only the broken piece gives 16√3/3 ≈ 9.24 m.
Answer: A) 8√3 m

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