- A3 times as long
- B4/3 times as long
- Cone third as long
- D√3 times as long
Step-by-Step Solution
A pole of height h casts a shadow h·cot60° = h/√3 the first time and h·cot45° = h the second time, so the second is h ÷ (h/√3) = √3 ≈ 1.73 times the first. The height cancels, so the factor is the same for any pole. A factor of 3 belongs to the pair 60° and 30°, not 60° and 45°; comparing the altitudes themselves (60 ÷ 45) suggests 4/3; and the shadow lengthens as the sun sinks, so 'one third' has the change backwards.
Answer: D) √3 times as long