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A vertical tower 60 m high stands on level ground with points P and Q on opposite sides of its foot. The angles of elevation of the top from P and Q are 45° and 60°. The distance PQ is:

Competition practiceTrigonometry
  • A(60 + 60√3) m
  • B120 m
  • C(60 − 20√3) m
  • D(60 + 20√3) m

Step-by-Step Solution

The distances from the foot are 60/tan45° = 60 m and 60/tan60° = 60/√3 = 20√3 m. Since P and Q are on opposite sides, PQ = 60 + 20√3 ≈ 94.64 m.
Answer: D) (60 + 20√3) m

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