Practice30Create account

For every angle θ, the value of siθ + si(90° − θ) + si(180° + θ) + si(270° − θ) is:

Competition practiceTrigonometry
  • A4
  • B1
  • C0
  • D2

Step-by-Step Solution

Reduce each allied angle: sin(90° − θ) = cosθ, sin(180° + θ) = −sinθ and sin(270° − θ) = −cosθ. Squaring wipes out both minus signs, so the four terms are siθ, coθ, siθ and coθ, which pair up into 1 + 1 = 2. Check at θ = 37°: 0.3624 + 0.6376 + 0.3624 + 0.6376 = 2.000. Counting each squared term as a full 1 gives 4; pairing only the first two and stopping gives 1; and 0 expects the minus signs to cancel the terms — but they are inside squares, so they never survive.
Answer: D) 2

Master this topic in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Trigonometry practice questions

More Trigonometry practice

All the angles θ with 0° ≤ θ ≤ 180° for which sin2θ = cosθ are:If sinθ + cosθ = a and sin³θ + cos³θ = b, then a and b always satisfy:The three sides of a triangle measure 3 cm, 5 cm and 7 cm. Its area is:In triangle ABC the angle C is a right angle and sinA = 3/5. The value of sinA·sinB +…For every θ at which every factor is defined, (cosecθ − sinθ)(secθ − cosθ)(tanθ + cotθ)…