If 5(secθ − tanθ) = 3, then 5(secθ + tanθ) equals:

The given statement says secθ − tanθ = 3/5, and because (secθ + tanθ)(secθ − tanθ) = se$c^2$θ − ta$n^2$θ = 1, the companion is secθ + tanθ = 5/3. The question asks for FIVE times that, namely 25/3 ≈ 8.33. Check: secθ − tanθ = 0.6 and secθ + tanθ = 1.667 give secθ = 1.1333 and tanθ = 0.5333, whose squares differ by exactly 1. Dropping the factor 5 leaves 5/3, taking the reciprocal of the printed number 3 gives 1/3, and simply copying that number gives 3.