- Asin(A + B) = sinC
- Bcot(A + B) = cotC
- Ccos(A + B) = −cosC
- Dtan(A + B) = −tanC
Step-by-Step Solution
In a triangle A + B = 180° − C. The sine of a supplement is unchanged, but the cosine, tangent and cotangent all flip sign, so cot(A + B) = −cotC, not cotC. Check with A = B = C = 60°: cot120° = −0.577 while cot60° = +0.577.
Answer: B) cot(A + B) = cotC