- A1 − secA·cosecA
- BsecA·cosecA
- C1 + tanA·cotA
- D1 + secA·cosecA
Step-by-Step Solution
Combining over a common denominator reduces the sum to 1 + tanA + cotA, and tanA + cotA = 1/(sinA·cosA) = secA·cosecA, giving 1 + secA·cosecA.
Answer: D) 1 + secA·cosecA