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The value of [cos(90° − θ)·secθ·tanθ] ÷ [cosec(90° − θ)·sin(90° − θ)·cot(90° − θ)] is:

Competition practiceTrigonometry
  • Atanθ
  • Bcotθ
  • Csinθ
  • Dseθ

Step-by-Step Solution

The numerator is sinθ·secθ·tanθ = taθ. In the denominator cosec(90° − θ) = secθ, sin(90° − θ) = cosθ and cot(90° − θ) = tanθ, so it equals secθ·cosθ·tanθ = tanθ. The quotient is taθ/tanθ = tanθ.
Answer: A) tanθ

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