An algebraic identity is an equation that is true for every value of the letters. The standard identities let you expand brackets, factorise expressions and do some arithmetic quickly in your head.
Formulas
Square of a sum
(a+b)2=a2+2ab+b2
Square of a difference
(a−b)2=a2−2ab+b2
Difference of two squares
a2−b2=(a+b)(a−b)
Product of two binomials
(x+a)(x+b)=x2+(a+b)x+ab
Worked examples
Example 1. Expand (3x+2)2.
Use (a+b)2=a2+2ab+b2 with a=3x,b=2.
=9x2+2(3x)(2)+4=9x2+12x+4.
Answer: 9x2+12x+4
Example 2. Find 1032 using an identity.
103=100+3,so1032=1002+2(100)(3)+32.
=10000+600+9=10609.
Answer: 10 609
Example 3. Find 98×102 using an identity.
98×102=(100−2)(100+2)=1002−22.
=10000−4=9996.
Answer: 9996
Example 4. Factorise 25x2−16.
25x2=(5x)2 and 16=42, a difference of two squares.
25x2−16=(5x+4)(5x−4).
Answer: (5x+4)(5x−4)
Common mistakes
Writing (a+b)2=a2+b2. The middle term 2ab is always there.
Getting the sign of the middle term wrong. It is +2ab for a sum and −2ab for a difference.
Trying to factorise a sum of two squares like a2+b2 with the difference-of-squares identity. It only works for a difference.
Practice questions with answers
1. Which expression is the correct expansion of (a+b)2 ?
Aa2+b2
Ba2+2ab+b2
Ca2−2ab+b2
Da2+ab+b2
Show answer
Answer: B) a2+2ab+b2
The standard identity is (a+b)2=a2+2ab+b2.
2. Expand (x+3)2.
Ax2+6x+6
Bx2+6x+9
Cx2+9
Dx2+3x+9
Show answer
Answer: B) x2+6x+9
(a+b)2=a2+2ab+b2:x2+2(x)(3)+9=x2+6x+9. Leaving out the middle term 6x is the most common slip.
3. Multiply: 4x×(2x+3).
A8x2+12x
B8x+12x
C6x2+7x
D8x2+12
Show answer
Answer: A) 8x2+12x
Distribute: 4x×2x+4x×3=8x2+12x.
4. Priya checks that for any number x, the expression x2−(x−1)(x+1) is always the same value. What is that constant value?
A0
B2
C1
D3
Show answer
Answer: C) 1
(x−1)(x+1)=x2−1, so x2−(x2−1)=1 for every x. The constant value is 1.
5. Factorise 27x3+y3+z3−9xyz.
A(9x+y+z)(x2+y2+z2−xy−yz−xz)
B(3x+y+z)3
C(3x+y+z)(9x2+y2+z2−3xy−yz−3xz)
D(3x+y+z)(9x2+y2+z2+3xy+yz+3xz)
Show answer
Answer: C) (3x+y+z)(9x2+y2+z2−3xy−yz−3xz)
With a=3x,b=y,c=z:3abc=9xyz, so use a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca).
6. Neha writes (2x+3)2=4x2+9. Substituting x=1 into both sides, what does the check show?
ABoth sides give 13, so Neha is correct
BLeft side is 25 but right side is 13 — the middle term 12x is missing
CLeft side is 13 but right side is 25 — the 3 should not be squared
DLeft side is 25 and right side is 25, so the check proves nothing
Show answer
Answer: B) Left side is 25 but right side is 13 — the middle term 12x is missing
At x=1 the left side is (2+3)2=25, while Neha's right side gives 4 + 9 = 13. The sides disagree, so her expansion is wrong. The correct one is (2x+3)2=4x2+2(2x)(3)+9=4x2+12x+9, which at x=1 gives 4 + 12 + 9 = 25 and matches. (a+b)2 always carries a middle term.
An equation that holds for all values of the variables, unlike an ordinary equation that holds only for particular values.
What are the standard algebraic identities?
(a+b)2,(a−b)2,a2−b2 and (x+a)(x+b), as listed above.
How do identities help with arithmetic?
They turn awkward products into easy ones, such as 992=(100−1)2=9801 and 51×49=502−1=2499.
How do I know which identity to use?
Look at the shape. A bracket squared means the first two; two squares being subtracted means a2−b2; two brackets with the same variable means (x+a)(x+b).