An arithmetic progression (AP) is a list of numbers in which each term is found by adding the same number, the common difference d, to the term before it. For example 3, 7, 11, 15, … is an AP with first term a=3 and d=4.
Formulas
The nth term
an=a+(n−1)d
Sum of the first n terms
Sn=2n[2a+(n−1)d]=2n(a+l)
Common difference
d=a2−a1=a3−a2=…
Worked examples
Example 1. Find the 20th term of the AP 3, 7, 11, 15, …
a=3 and d=7−3=4.
a20=3+(20−1)×4=3+76=79.
Answer: 79
Example 2. Which term of the AP 5, 9, 13, … is 101?
a=5,d=4. Set 5+(n−1)×4=101.
(n−1)×4=96, so n−1=24 and n=25.
Answer: The 25th term
Example 3. Find the sum of the first 15 terms of 2, 5, 8, …
a=2,d=3,n=15.
S15=215[2×2+14×3]=215×46=345.
Answer: 345
Example 4. Find the sum of the first 100 natural numbers.
1, 2, 3, …, 100 is an AP with a=1 and last term l=100.
S100=2100(1+100)=50×101=5050.
Answer: 5050
Common mistakes
Using n instead of n−1 in the nth term formula. The first term already counts once, so only n−1 steps of d are added.
Finding d the wrong way round. It is a later term minus the earlier one, so for 20, 17, 14, … it is −3, not 3.
Mixing up an (one term) and Sn (the total of the first n terms).
Practice questions with answers
1. Find the 10th term of AP 3, 8, 13, 18, ….
A48
B53
C50
D43
Show answer
Answer: A) 48
a = 3, d = 5. a₁₀ = 3 + 9·5 = 48.
2. For an AP, the nth term is given by an=a+(n−1)d. What does 'd' represent here?
AThe first term
BThe common difference
CThe number of terms
DThe last term
Show answer
Answer: B) The common difference
In an=a+(n−1)d, 'a' is the first term and 'd' is the common difference (the fixed gap between consecutive terms).
3. The sum of the first n terms of an AP with first term a and common difference d is given by which formula?
AS=2n[2a+(n−1)d]
BS=2n[a+(n−1)d]
CS=n[2a+(n−1)d]
DS=2n[2a + nd]
Show answer
Answer: A) S=2n[2a+(n−1)d]
The standard formula for the sum of n terms of an AP is Sn=2n[2a+(n−1)d].
4. The numbers 7, x and 15 are in AP. Find x.
A8
B22
C10
D11
Show answer
Answer: D) 11
For three terms in AP the middle one is the average of the other two: x=(7+15)/2=11. 8 is 15 − 7; 22 forgets to halve.
5. The first term of an AP of monthly rents is Rs 5000 and the 6th month rent is Rs 6500. What is the monthly increase?
A600
B300
C330
D270
Show answer
Answer: B) 300
a6−a=5d=6500−5000=1500,sod=51500=Rs300.
6. The first term of an AP is 3 and the sum of its first 9 terms is 171. Find its common difference.
A5
B3
C4
D8
Show answer
Answer: C) 4
S9=29[2(3)+8d]=171 → 6+8d=38 → 8d=32 → d=4. Check with the AP 3, 7, 11, …: S9=29(6+32)=171.