A cyclist covers 40 km on day 1 of a tour and 5 km less each successive day due to fatigue. For how many days can he ride before his daily distance would become 0 or negative (i.e. the last day with a positive distance)?

Question

Accepted Answer

8 days. a = 40, d = -5. an = 40 + (n-1)(-5) = 45 - 5n. Positive while 45 - 5n > 0, i.e. n < 9. On day 8: 45-40 = 5 km (positive); day 9: 0 km. Last positive day = 8.

A cyclist covers 40 km on day 1 of a tour and 5 km less each successive day due to fatigue.
For how many days can he ride before his daily distance would become 0 or negative (i.e. the last day with a positive distance)?

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More Class 10 AP Word Problems practice

A cyclist covers 40 km on day 1 of a tour and 5 km less each successive day due to fatigue.For how many days can he ride before his daily distance would become 0 or negative (i.e. the last day with a positive distance)?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 AP Word Problems practice

A cyclist covers 40 km on day 1 of a tour and 5 km less each successive day due to fatigue.
For how many days can he ride before his daily distance would become 0 or negative (i.e. the last day with a positive distance)?