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Numbers between 100 and 200 that are divisible by 9 are 108, 117, 126, ..., 198.
What is their sum?

Class 10AP Word ProblemsAlgebra — Sequences

A1683
B1530
C1800
D1620

Step-by-Step Solution

a = 108, d = 9

, last = 198.

n : 198 = 108 + (n - 1) 9

gives

n - 1 = 10, n = 11

. Sum =

\frac{11}{2} (108 + 198) = \frac{11}{2}

(306) = 11 \times 153 = 1683

.

Answer: A) 1683

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