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For what value of p are the points (p,-1), (2,1) and (4,5) collinear (zero triangle area)?

Class 10Area of a Triangle (Coordinates)Geometry — Coordinates

A3
B0
C1
D2

Step-by-Step Solution

Area =

\frac{1}{2} ∣ p (1 - 5) + 2 (5 - (- 1)) + 4 ((- 1) - 1) ∣ = \frac{1}{2} ∣ - 4 p + 12 - 8∣ = \frac{1}{2} ∣4 - 4 p

| = 0, so

p = 1

.

Answer: C) 1

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