A photograph carries a triangular logo of area 45 cm^2. The photograph is reduced so that every length becomes two-thirds of what it was, and the logo stays similar to itself. Find the area of the logo in the reduced photograph (in cm^2).

Question

Accepted Answer

20. Area factor = (2/3 )^2 = 4/9, so the new area = 45 × 4/9 = 20 cm^2. Using the length factor 2/3 on the area gives 30 cm^2, the commonest error; 22.5 is just half of 45, and 101.25 uses 9/4, enlarging when the photo was reduced.

A photograph carries a triangular logo of area $45 cm^{2}$ . The photograph is reduced so that every length becomes two-thirds of what it was, and the logo stays similar to itself.
Find the area of the logo in the reduced photograph (in $cm^{2}$ ).

Step-by-Step Solution

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More Class 10 Areas of Similar Triangles practice

A photograph carries a triangular logo of area 45cm2. The photograph is reduced so that every length becomes two-thirds of what it was, and the logo stays similar to itself.Find the area of the logo in the reduced photograph (in cm2).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Areas of Similar Triangles practice

A photograph carries a triangular logo of area $45 cm^{2}$ . The photograph is reduced so that every length becomes two-thirds of what it was, and the logo stays similar to itself.
Find the area of the logo in the reduced photograph (in $cm^{2}$ ).