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Triangle ABC ~ triangle PQR. The altitude from A is 6 cm and the altitude from P is 10 cm.
If area(ABC) = $27 cm^{2}$ , find area(PQR) in $cm^{2}$ .

Class 10Areas of Similar TrianglesGeometry — Similarity

A150
B67
C75
D83

Step-by-Step Solution

Area ratio =

(a lt i t u d er a t i o)^{2} = (\frac{6}{10})^{2} = \frac{9}{25}

. So area(PQR) =

27 \times \frac{25}{9} = 75 cm^{2}

.

Answer: C) 75

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