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Find the value of so that , and are three consecutive terms of an AP.

Class 10Arithmetic ProgressionsAlgebra — Sequences
  • A12
  • B7
  • C5
  • D6

Step-by-Step Solution

For an AP, 2(middle) = first + last: → → → .
Answer: D) 6

Key idea: n-th term formula

**aₙ = a + (n − 1)d**

Where a is the first term, d is the common difference, n is the position.

**Why**: a₁ = a; a₂ = a + d; a₃ = a + 2d; … aₙ = a + (n − 1)d. Each step adds another d.

**Example**: AP 3, 7, 11, 15, …. Find the 20th term.
a = 3, d = 4. a₂₀ = 3 + 19·4 = 79.

**Reverse use**: 'In the AP 5, 11, 17, …, which term is 89?' a + (n−1)d = 89 → 5 + 6(n−1) = 89 → n = 15.

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