Surveyor Anita reads AD = (3x + 4) m, DB = (x + 1) m, AE = (4x + 2) m and EC = (2x - 1) m in triangle ABC, where DE || BC. Find x (positive value) using BPT.

Question

Accepted Answer

2. 3x+4/x+1 = 4x+2/2x-1. Cross: (3x+4)(2x-1) = (x+1)(4x+2). LHS = 6x^2 -3x +8x -4 = 6x^2 +5x -4. RHS = 4x^2 +2x +4x +2 = 4x^2 +6x +2. So 6x^2+5x-4 = 4x^2+6x+2, 2x^2 - x - 6 = 0, (2x+3)(x-2)=0, x = 2.

Surveyor Anita reads AD = $(3 x + 4)$ m, DB = $(x + 1)$ m, AE = $(4 x + 2)$ m and EC = $(2 x - 1)$ m in triangle ABC, where DE || BC. Find $x$ (positive value) using BPT.

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More Class 10 Basic Proportionality Theorem practice

Surveyor Anita reads AD = (3x+4) m, DB = (x+1) m, AE = (4x+2) m and EC = (2x−1) m in triangle ABC, where DE || BC. Find x (positive value) using BPT.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Basic Proportionality Theorem practice

Surveyor Anita reads AD = $(3 x + 4)$ m, DB = $(x + 1)$ m, AE = $(4 x + 2)$ m and EC = $(2 x - 1)$ m in triangle ABC, where DE || BC. Find $x$ (positive value) using BPT.