Practice30 Create account

Using only distances, when are three points A, B and C collinear with B lying between A and C?

Class 10Classifying Shapes by CoordinatesGeometry — Coordinates

A $A B^{2} + B C^{2} = A C^{2}$
B $A B \times BC = A C$
CAB + BC = AC
DAB = BC = AC

Step-by-Step Solution

If

B

is on segment

A C

, the two parts add up to the whole:

A B + BC = A C . A B^{2} + B C^{2} = A C^{2}

is the test for a right angle at

B

instead.

Answer: C) AB + BC = AC

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Classifying Shapes by Coordinates practice questions

More Class 10 Classifying Shapes by Coordinates practice

ABCD has vertices A(0, 0), B(5, 0), C(8, 4) and D(3, 4). It is a rhombus. How long is…Two opposite corners of a square tile pattern are A(2, 3) and C(6, 7). What is the side…For what positive value of k is the triangle with vertices A(0, 0), B(6, 0) and C(3, k)…Name the type of quadrilateral formed by A(−2, −1), B(4, 0), C(3, 3) and D(−3, 2), taken…What type of quadrilateral do the points (−1, −2), (1, 0), (−1, 2) and (−3, 0) form,…