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Two dice are thrown together.
The probability of getting a sum of 7 is $\frac{6}{36}$ .
What is the probability of NOT getting a sum of 7?

Class 10Complementary EventsStatistics

A $\frac{30}{36}$
B $\frac{6}{36}$
C $\frac{5}{36}$
D $\frac{31}{36}$

Step-by-Step Solution

Sums of 7: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6 outcomes. P(not 7)

= 1 - \frac{6}{36} = \frac{30}{36}

.

Answer: A)

\frac{30}{36}

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