The diagonal of a rectangular field is 13 m. The length is 7 m more than the width. With width x, x^2 + (x + 7)^2 = 169, which simplifies to x^2 + 7x - 60 = 0. Find the width by completing the square.

Question

Accepted Answer

5. x^2 + 7x = 60, add 49/4: (x + 7/2)^2 = 60 + 49/4 = 289/4, x + 7/2 = 17/2, x = 5 m.

The diagonal of a rectangular field is 13 m. The length is 7 m more than the width.
With width $x, x^{2} + (x + 7)^{2} = 169$ , which simplifies to $x^{2} + 7 x - 60 = 0$ .
Find the width by completing the square.

Step-by-Step Solution

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More Class 10 Completing the Square practice

The diagonal of a rectangular field is 13 m. The length is 7 m more than the width.With width x,x2+(x+7)2=169, which simplifies to x2+7x−60=0.Find the width by completing the square.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Completing the Square practice

The diagonal of a rectangular field is 13 m. The length is 7 m more than the width.
With width $x, x^{2} + (x + 7)^{2} = 169$ , which simplifies to $x^{2} + 7 x - 60 = 0$ .
Find the width by completing the square.