A goldsmith in Jaipur melts a metal cuboid of dimensions 77 cm $x$ 72 cm $x$ 7 cm and casts it into a sphere.
Find the radius of the sphere (in cm). (use π = $\frac{22}{7}$ )

Question

A goldsmith in Jaipur melts a metal cuboid of dimensions 77 cm x 72 cm x 7 cm and casts it into a sphere. Find the radius of the sphere (in cm). (use π = 22/7)

Accepted Answer

21. Cuboid V = 77*72*7 = 38808 cm^3. 4/3*22/7*r^3 = 38808 => 88/21*r^3 = 38808 => r^3 = 38808*21/88 = 9261 => r = 3√9261 = 21 cm.

A goldsmith in Jaipur melts a metal cuboid of dimensions 77 cm $x$ 72 cm $x$ 7 cm and casts it into a sphere.
Find the radius of the sphere (in cm). (use π = $\frac{22}{7}$ )

Step-by-Step Solution

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More Class 10 Conversion of Solids practice

A goldsmith in Jaipur melts a metal cuboid of dimensions 77 cm x 72 cm x 7 cm and casts it into a sphere.Find the radius of the sphere (in cm). (use π = 722​)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Conversion of Solids practice

A goldsmith in Jaipur melts a metal cuboid of dimensions 77 cm $x$ 72 cm $x$ 7 cm and casts it into a sphere.
Find the radius of the sphere (in cm). (use π = $\frac{22}{7}$ )