- A(-7, 0)
- B(7, 0)
- C(0, 7)
- D(-7, 7)
Step-by-Step Solution
Let point be → → → → . Point = (−7, 0).
Answer: A) (-7, 0)
Find the coordinates of the point on the -axis that is equidistant from (2, −5) and (−2, 9).
Class 10Coordinate GeometryGeometry — Coordinates
Key idea: Distance formula
**Distance** between two points P₁, ₁) and Q₂, ₂):
**PQ = **
This is just the Pythagoras theorem applied to the right triangle formed with horizontal and vertical legs.
**Example**: Distance between (3, 4) and (7, 1).
= .
**Special distance from origin**: distance of from (0, 0) is .
**PQ = **
This is just the Pythagoras theorem applied to the right triangle formed with horizontal and vertical legs.
**Example**: Distance between (3, 4) and (7, 1).
= .
**Special distance from origin**: distance of from (0, 0) is .
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