- A(0, 9)
- B(9, 0)
- C(0, 4)
- D(0, -9)
Step-by-Step Solution
Let point be (0, → → → → . Point = (0, 9).
Answer: A) (0, 9)
Find the point on the -axis which is equidistant from the points A(6, 5) and B(−4, 3).
Class 10Coordinate GeometryGeometry — Coordinates
Key idea: Distance formula
**Distance** between two points P₁, ₁) and Q₂, ₂):
**PQ = **
This is just the Pythagoras theorem applied to the right triangle formed with horizontal and vertical legs.
**Example**: Distance between (3, 4) and (7, 1).
= .
**Special distance from origin**: distance of from (0, 0) is .
**PQ = **
This is just the Pythagoras theorem applied to the right triangle formed with horizontal and vertical legs.
**Example**: Distance between (3, 4) and (7, 1).
= .
**Special distance from origin**: distance of from (0, 0) is .
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