DE || BC in triangle ABC, cutting AB at D and AC at E so that AD : DB = 3 : 2. The line DE divides the triangle into triangle ADE and trapezium DBCE. Find the ratio of the area of triangle ADE to the area of triangle ABC.

Question

Accepted Answer

9 : 25. AD/AB = 3/(3+2) = 3/5. Triangle ADE ~ triangle ABC, so area ratio = (3/5)^2 = 9/25.

DE || BC in triangle ABC, cutting AB at D and AC at E so that AD : DB = 3 : 2. The line DE divides the triangle into triangle ADE and trapezium DBCE.
Find the ratio of the area of triangle ADE to the area of triangle ABC.

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More Class 10 Criteria for Similarity practice

DE || BC in triangle ABC, cutting AB at D and AC at E so that AD : DB = 3 : 2. The line DE divides the triangle into triangle ADE and trapezium DBCE.Find the ratio of the area of triangle ADE to the area of triangle ABC.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Criteria for Similarity practice

DE || BC in triangle ABC, cutting AB at D and AC at E so that AD : DB = 3 : 2. The line DE divides the triangle into triangle ADE and trapezium DBCE.
Find the ratio of the area of triangle ADE to the area of triangle ABC.